What are the solution(s) to the following system of equations #y = x^2# and y = –x?

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Answer 1 · 2016-07-20T03:21:27

Since #y = x^2# and #y = -x#:

#x^2 = -x#

#x^2 + x = 0#

#x(x + 1) = 0#

#x = 0 and -1#

#y = 0^2 and (-1)^2 = 0 and 1#

Hence, the solution set is #{0, 0}# and #{-1, 1}#.

Hopefully this helps!