# What are the solutions to #5x^2+27x+10=0#?

##### 2 Answers

Jun 15, 2017

#### Explanation:

#rArr5x^2+25x+2x+10=0larr 25x+2x=27x#

#rArrcolor(red)(5x)(x+5)+color(red)(2)(x+5)=0#

#rArr(x+5)(color(red)(5x+2))=0#

#"equating each factor to zero"#

#rArrx+5=0rArrx=-5#

#5x+2=0rArrx=-2/5#

Jun 16, 2017

#### Explanation:

Solving by the new Transforming Method (Google, Socratic Search).

Transformed equation:

Proceeding: Find 2 real roots of y', then, divide them by a = 5.

Find 2 real roots knowing sum (-b = -27) and product (c = 50). They are -2 and -25.

Back to y, the 2 real roots are:

NOTE:

There are no factoring by grouping and no solving the 2 binomials.