What are the vertical asymptotes of the graph y=(2x-6)/(x^3-x)?

$x = 0 , x = 1$ and $x = - 1$
So ${x}^{3} - x = 0$ is equivalent with $x \left({x}^{2} - 1\right) = 0$, so $x = 0$ or ${x}^{2} = 1$. By taking the square root of the second one, we find $x = 1$ and $x = - 1$. So all the answers are $x = 0 , x = 1$ and $x = - 1$.