# What are the x-intercepts of y=x^2+2x-15?

Oct 26, 2014

By setting it equal to zero,

${x}^{2} + 2 x - 15 = 0$

by factoring out,

$\left(x + 5\right) \left(x - 3\right) = 0$

by setting each factor equal to zero,

$\left\{\begin{matrix}x + 5 = 0 R i g h t a r r o w x = - 5 \\ x - 3 = 0 R i g h t a r r o w x = 3\end{matrix}\right.$

Hence, the $x$-intercepts are: $x = - 5 , 3$.

I hope that this was helpful.