What are the x-intercepts of y = x^2 - 4x - 12?

Oct 28, 2015

Y intercept = -12
X-intercept = 6,-2

Explanation:

For the intercepts, you need to understand first what means x-intercept and y-intercept.

X intercept means the point at which the line or the curve that intersects x-axis, and y intercept is the intersection at y-axis.

For the y intercept,
we know at y-axis, x=0

SO,

y =${0}^{2} - 4 \cdot 0 - 12$

= -12

So -12 is the y-intercept,

For the x-intercept, we let y=0

${x}^{2} - 4 x - 12$=0

${x}^{2} - \left(6 - 2\right) - 12$=0

${x}^{2} - 6 x + 2 x - 12$=0

$x \left(x - 6\right) + 2 \left(x - 6\right)$=0

(x-6)(x+2) =0

So either Or.
x-6=0 x+2 =0
x=6 x=-2

So 6 and -2 are the x-intercepts.