Question

What are the zero(s) `4x^2-6x+13=0`?

Answer 1

Solve `y = 4x^2 - 6x + 13 = 0`

Explanation:

`y = 4x^2 - 6x + 13.`
`D = b^2 - 4ac = 36 - 208 < 0.`
There are no real roots. The upward parabola doesn't intercept the x-axis.