# What are the zero(s) for #f(x) = 2x^6 +x^3+3#?

##### 1 Answer

Oct 24, 2015

#### Explanation:

Using the quadratic formula we find:

#x^3 = (-1+-sqrt(1^2-4xx2xx3))/(2*2)#

#=(-1+-sqrt(-23))/4 = (-1+-i sqrt(23))/4#

So

#x_(1,2) = root(3)((-1+-i sqrt(23))/4)#

#x_(3,4) = omega root(3)((-1+-i sqrt(23))/4)#

#x_(5,6) = omega^2 root(3)((-1+-i sqrt(23))/4)#

where