What are the zeros of the polynomial function #F(x) = 6x(x+5)^2(x-3)(7x-14)#?

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Answer 1 · 2017-10-11T13:11:07

#x= 0 , 2 ,3 -5#

We are looking to solve #6x(x+5)^2(x-3)(7x-14)=0#

Since this is already factored we can just find the values of #x# which make each factor #0#

#x=0#

#6(0)(x+5)^2(x-3)(7x-14)=0#

#x=-5#

#6x(0)^2(x-3)(7x-14)=0#

#x=3#

#6x(x+5)^2(0)(7x-14)=0#

#x=2)#

#6x(x+5)^2(x-3)(0)=0#