What are three irrational number between -11 and -12?

1 Answer

#(-11)-(pi-3), (-11)-(sqrt2-1), (-11)-(sqrt3-1)#

Explanation:

The difficult part to this question is not in identifying irrational numbers between #-11# and #-12# (there are an infinite number of them) - it's in expressing them. What is an easy way to express an unending, non-repeating set of digits that by definition cannot be expressed as a fraction composed of integers?

One way is to take a few well-known irrational numbers, alter them slightly, and present those as solutions. For instance, #pi# is a well known irrational number:

3.1415...

So what if we simply change the "whole number" part of #pi# but keep the unending string of digits:

#-11.1415...#

and if we want to express it a bit more clearly, we can say:

#(-11)-(pi-3)=-11-0.1415...=-11.1415...#

We can do the same thing with #sqrt2=1.4142...# and #sqrt3=1.732...#:

#(-11)-(sqrt2-1)=-11-0.4142...=-11.4142...#
#(-11)-(sqrt3-1)=-11-0.732...=-11.732...#