What could the #""^(n)"Pr"# mean in #""^(n)"PrNH"_2#?

Is it "normal propyl", like in #n#-pentane, or something else? #"Pr"# as an atom is praseodymium, but is it possible that #""^(n)"Pr"# is normal-propyl?

I've seen #""^(i)"Pr"# indicate isopropyl before.

1 Answer
anor277
Dec 2, 2017

It is #"n-propyl"#, where #n# is short for #"normal"# as you suspected....three carbon atoms in a straight chain...

Explanation:

And thus #"n-propyl"# specifies the STRAIGHT CHAIN....#H_3C-CH_2CH_2X#, and isopropyl specifies the branched chain, #Pr^(i)-=-CH(CH_3)_2#.

As for #"praesodymium"#, I doubt any organic chemist could even find a lanthanide.....

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