# What does (6+4i)/(3-i) equal?

Oct 21, 2015

I found: $\frac{7}{5} + \frac{9}{5} i$
$\frac{6 + 4 i}{3 - i} \cdot \textcolor{red}{\frac{3 + i}{3 + i}} =$
$\frac{\left(6 + 4 i\right) \left(3 + i\right)}{9 + 1} =$ where you used the fact that ${i}^{2} = - 1$
$\frac{18 + 6 i + 12 i - 4}{10} = \frac{14}{10} + \frac{18}{10} i = \frac{7}{5} + \frac{9}{5} i$