What fuction satisfies the following coordinates? #(0,1)(52,2)(104,4)(156,8)(208,16)(260,32)(312,64)# and so on?

3 Answers

#x÷52=(ln (y))÷(ln (2))#

Explanation:

#x# values are
Multiples of #52# starting from 0,1,2,3,4,5,6,..
#y# values are
Powers of 2 starting from
#0,1,2,3,4,5,6#,...
Thus #x=52a#
#a=x÷52#
where #a=(0,1,2,3,4,5,6,...)#
While #y=2^a# where #a=(0,1,2,3,4,5,6,...)#
Simplifying
#a=log_2 (y)#
By change of base rule that #log_a(b)=log_c(b)/(log_c(a))#
#log_2(y) = ln (y)÷ln (2)# We have set #c# as #e#.
Now,
#a=ln (y)÷ln (2)#
Equating a from the expressions
#x÷52=(ln (y))÷(ln (2))#

Jan 31, 2018

#y = 2^(x/52)#

Jan 31, 2018

The answer is #y=2^(x/52)#

Explanation:

Let 's make a table

#color(white)(aaaa)##n##color(white)(aaaa)##0##color(white)(aaaaa)##1##color(white)(aaaaaa)##2##color(white)(aaaaa)##3##color(white)(aaaaaa)##4##color(white)(aaaaaa)##5##color(white)(aaaaaa)##6#

#color(white)(aaaa)##x##color(white)(aaaa)##0##color(white)(aaaa)##52##color(white)(aaaa)##104##color(white)(aaaa)##156##color(white)(aaaa)##208##color(white)(aaaa)##260##color(white)(aaaa)##312#

#color(white)(aaaa)##y##color(white)(aaaa)##1##color(white)(aaaaa)##2##color(white)(aaaaaa)##4##color(white)(aaaaaa)##8##color(white)(aaaaa)##16##color(white)(aaaaa)##32##color(white)(aaaaa)##64#

From the table, we can see that

#y=2^n#, #AA n in NN#

and

#x=26xx2n#

Eliminating #n# from the #2# equations,

#n=x/52#

#y=2^(x/52)#