What is #10/33 -:# 1#2/11#?

1 Answer
Mar 16, 2018

See a solution process below:

Explanation:

First, convert the mixed number to an improper fraction:

#1 2/11 = 1 + 2/11 = (11/11 xx 1) + 2/11 = 11/11 + 2/11 = (11 + 2)/11 = 13/11#

Next, we can rewrite the expression as:

#10/33 -: 1 2/11 => 10/33 -: 13/11 => (10/33)/(13/11)#

Now, we can use this rule for dividing fractions to evaluate the expression:

#(color(red)(a)/color(blue)(b))/(color(green)(c)/color(purple)(d)) = (color(red)(a) xx color(purple)(d))/(color(blue)(b) xx color(green)(c))#

#(color(red)(10)/color(blue)(33))/(color(green)(13)/color(purple)(11)) => (color(red)(10) xx color(purple)(11))/(color(blue)(33) xx color(green)(13)) => (color(red)(10) xx cancel(color(purple)(11))color(purple)(1))/(cancel(color(blue)(33))color(blue)(3) xx color(green)(13)) => (color(red)(10) xx color(purple)(1))/(color(blue)(3) xx color(green)(13)) => 10/39#