What is #(-19y^0 z^4)/(-3z^16)#?

Note: The numbers after the ^ sign represent exponents

1 Answer
Jan 5, 2016

Answer:

#(-19y^0z^4)/(-3z^16)=19/(3z^12)#

Explanation:

#(-19y^0z^4)/(-3z^16)#

Dividing two negative numbers equals a positive number.

#(19y^0z^4)/(3z^16)#

Apply exponent rule #a^0=1 rArr y^0=1#.

#(19xx1xxz^4)/(3z^16)#

Simplify.

#(19z^4)/(3z^16)#

Apply exponent rule #a^m/a^n=a^((m-n))#+

#(19z^((4-16)))/(3)#

Simplify.

#(19z^-12)/3#

Apply negative exponent rule #a^(-m)=1/a^m#.

#19/(3z^12)#