What is #(-2/3)/(1/4) + 1/2 xx 1/2 xx 1/3#?

It confuses me, too many fractions.

It confuses me, too many fractions.

2 Answers
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Feb 6, 2018

Answer:

#= -2 7/12#

Explanation:

There is no need to get confused....... count the number of terms and then simplify each term separately.

In the last step you can add the answers to the terms together,

Terms are separated by #+ and -# signs, so there are #2# terms:

#color(blue)((-2/3)/(1/4))" "+" "color(red)(1/2xx1/2xx1/3)#

#=color(blue)(-2/3 div1/4)" "+" "color(red)(1/12" "(larr "top x top x top")/(larr"bottom x bottom x bottom")#
#color(white)(xx.xxx)darr#
#=color(blue)(-2/3 xx4/1)" "+" "color(red)(1/12)#

#=color(blue)(-8/3)" "+" "color(red)(1/12)" "larr# find a common denominator
#" "darr#
#color(blue)(-8/3 xx 4/4)#
#" "darr#
#=color(blue)(-32/12" "+" "color(red)(1/12)" "larr# now add the numerators

#=(-32+1)/12#

#=-31/12#

#= -2 7/12#

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Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources
preview
?

Answer

Write a one sentence answer...

Answer:

Explanation

Explain in detail...

Explanation:

I want someone to double check my answer

Describe your changes (optional) 200

1
Feb 3, 2018

Answer:

#-31/12#

Explanation:

#(-2/3) / (1/4) + 1/2 xx 1/2 xx 1/3#

Divide #-2/3# by #1/4#

#(-2/3)/(1/4) = -2/3 xx 4/1 = - 8/3#

So

#-8/3 + 1/2 xx 1/2 xx 1/3#

Multiply #1/2# by #1/2#

#-8/3 + 1/4 xx 1/3#

Multiply #1/4# by #1/3#

#-8/3 + 1/12#

Use the common denominator

#-32/12 + 1/12#

Add #-32/12# and #1/12#

#-31/12#

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