What is #(2x^-5 y^3)^-5#?

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Answer 1 · 2018-04-30T17:01:06

#1/32x^25y^-15 = (x^25)/(32y^15)#

Given: #(2x^-5y^3)^-5#

To simplify use the exponent rule: #(x^m)^n = x^(m*n)#

#(2x^-5y^3)^-5 = 2^-5x^(-5*-5)y^(3*-5)#

# = 1/2^5 x^25y^-15#

# = 1/32 x^25 y^-15 #

Use the exponent rule: #x^-m = 1/x^m#

#= (x^25)/(32y^15)#