What is #2x^5y * 3x^2y#?

1 Answer
Ben
May 10, 2018

#6x^7y^2#

Explanation:

What we need to do here is first rewrite the expression, and then we can re-group everything:

#2x^5y*3x^2y=(2*x^5*y)*(3*x^2*y)#

#2x^5y*3x^2y=2*x^5*y*3*x^2*y#

As you can see, the expression can be written as one long multiplication expression. This allows us to re-order the expression, and group variables as we see fit:

#2x^5y*3x^2y=2*3*x^5*x^2*y*y#

#2x^5y*3x^2y=6*(x^5*x^2)*(y*y)#

Remember, when multiplying two of the same base number with different exponents, you simply add the exponent values together:

#2x^5y*3x^2y=6*x^(5+2)*y^(1+1)#

#2x^5y*3x^2y=6*x^7*y^2#

#2x^5y*3x^2y=color(green)(6x^7y^2#

Related questions
Impact of this question
5609 views around the world
You can reuse this answer
Creative Commons License