What is #3(x-4) = 2x - (3x - 4)# ?

I tried to solve it but when i plug the numbers, both sides are unequal.

1 Answer
Nov 30, 2017

#x=4#

Explanation:

Start of by distributing the numbers. So, do this:

Actual Equation:
#3(x-4)=2x-(3x-4)#

Actual Equation after distributing the numbers:
#3x-12=2x-3x+4#

Notice how I multiplied the #(x-4)# with #3# and the #(3x-4)# with the #-#. If you want to take the parentheses out, multiply the quantity inside the parentheses with the number that is directly outside of the parentheses. ex: #3(x-4)# or #-(3x-4)#

#-(3x-4)# became #-3x+4# because the number that is outside of the parentheses is #-1#, therefore multiplying #(3x-4)# with #-1# equals #-3x+4#.

Your second step would be to shift the #x# variables onto one side. I'm going to shift it to the left side.

#3x-12=2x-3x+4#

Step 3: Simplify the #2x-3x# into #-x#

#3x-12=-x+4#

Step 4: Add #x# to each side

#4x-12=4#

Step 5: Add #12# to each side

#4x=16#

Step 6: Divide each number by #4#

#x=4#