Question

What is `(3x^-4)(9x^2)`?

Answer 1

You multiply the numbers, and add the powers of the `x`'s

Explanation:

`=(3xx9)(x^(-4+2))=27x^-2or27/x^2`

Or:
You write `3x^-4=3/x^4`

Then you get:
`=3/x^4xx9x^2=3/(x^2*cancel(x^2))xx9cancel(x^2)=27/x^2or27x^-2`