# What is -3x^4y^2 * -x^0y^-4 * 2x?

$6 {x}^{5} {y}^{-} 2$
Using the property of exponents, that ${a}^{b} \cdot {a}^{c} = {a}^{b + c}$:
$- 3 {x}^{2} {y}^{2} \cdot - {x}^{0} {y}^{-} 4 \cdot 2 x = - \left(- 3\right) \cdot 2 \cdot {x}^{4 + 1 - 0} \cdot {y}^{2 - 4}$
$= 6 {x}^{5} {y}^{-} 2$ or $\frac{6 {x}^{5}}{y} ^ 2$. Note that the minus sign in front of ${x}^{0}$ does matter, even if it's attached to ${x}^{0}$, which is equal to $1$ anyway.