What is #4(4 - 2)^3 - 2(5 - 3)^3#?

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Answer 1 · 2016-04-16T20:36:45

#16#

Solve the brackets first

#(4-2)=2#
#(5-3)=2#

and insert these into the equation instead:

#4*2^3-2*2^3#

Now find workable values by expanding out,

#4*2^3=4*8=32#
#2*2^3=2*8=16#

and insert these back in for your final answer,

#32-16=16#