What is #(4m^-4n^3)^2#?

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Answer 1 · 2016-07-02T22:39:25

#(16 n^6)/m^8#

Raising a bracket to the power of 2 means it must be multiplied by itself:

#(4m^-4n^3)(4m^-4n^3)#

=#16 m^-8 n^6#.

Or using a Law of indices - when raising a power to a power,multiply the indices:

#4^(1xx2)m^(-4xx2)n^(3xx2) = 4^2m^-8 n^6#

However, we should not leave answers with negative indices.

=#(16 n^6)/m^8#