What is #(5- 6i ) ( 6- 2i )#?
1 Answer
Jul 26, 2018
Explanation:
#" note that "i^2=(sqrt(-1))^2=-1#
#"Expanding factors gives"#
#30-10i-36i+12i^2#
#=30-46i-12#
#=18-46i#
#" note that "i^2=(sqrt(-1))^2=-1#
#"Expanding factors gives"#
#30-10i-36i+12i^2#
#=30-46i-12#
#=18-46i#