What is (5- 6i ) ( 6- 2i )(5−6i)(6−2i)?
1 Answer
Jul 26, 2018
Explanation:
" note that "i^2=(sqrt(-1))^2=-1 note that i2=(√−1)2=−1
"Expanding factors gives"Expanding factors gives
30-10i-36i+12i^230−10i−36i+12i2
=30-46i-12=30−46i−12
=18-46i=18−46i