What is #5\div 0#?

2 Answers
Nov 27, 2016

Undefined

Explanation:

Division by #0# is not defined. When we divide a number #x# by a number #y#, it is the same as multiplying #x# by the multiplicative inverse of #y#, that is, the number #y^(-1)# which has the property #yxxy^(-1)=1#.

If #y# is not #0#, then that number is #1/y#, but if #y=0#, then there is no number #y^(-1)# fulfilling #0xxy^(-1) = 1#, because the product of #0# and any number is #0#. Thus we cannot divide by #0#.

Nov 27, 2016

#5 -: 0# is undefined

Explanation:

Another way of putting it:

Division by #0# is (almost) always undefined.

To see why in our current example, suppose there was some number #x# such that:

#x = 5 -: 0#

Then we could multiply both sides of the equation to find:

#x xx 0 = 5#

Note that any number multiplied by #0# is #0#, so this simplifies to:

#0 = 5#

which is false.

So our supposition that there was such a number #x# must have been false.