Question

What is `5y+x^2-:2` when `x=4` and `y=-3`?

Answer 1

-7.

Explanation:

Input all values into the equation.
`(5 * -3) + (4^2) / 2`
we find this using PEMDAS
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction.

We find the exponent first, and `4^2` is 16. Next is multiplication/divison. 16 divided by 2 is 8. We also multiply 5(-3) at this point.
The resulting equation is -15+8, which is equal to -7