What is #6.02 * 10^23# multiplied by #9.1 * 10^-31#?

1 Answer
Jun 9, 2016

You multiply the numbers and add the powers of #10#

Explanation:

#=(6.02xx9.2)xx(10^(23+ -31))#
#=55.38xx10^(-8)#

To make this valid scientific notation, we'd have to move the decimal point one to the left. This means the #10#-exponent goes one up:
#=5.538xx10^(-7)~~5.5xx10^(-7)#
(rounded to 2 significant digits, as in 9.1)