# What is (6^2-3^3)-:7?

Mar 13, 2018

Shown below...

#### Explanation:

First we find the value of what is in the brackets...

${6}^{2} - {3}^{3} = \left(6 \times 6\right) - \left(3 \times 3 \times 3\right)$

$= 36 - 27$

$= 9$

So now we are trying to find

$\frac{9}{7}$

This can't be simplified any further,

As a mixed fraction...

$\frac{9}{7} = \frac{7 + 2}{7} = \frac{7}{7} + \frac{2}{7} = 1 \frac{2}{7}$