What is #(6^3 - 2^6)/(2^3)# ?

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Answer 1 · 2016-07-20T21:50:27

#19#

The boring way would be to pick up a calculator and push buttons,,

Lets' explore a bit. Separate the fraction into two separate fractions each with its own denominator. At the same time write #6 = 2 xx3#

#(2xx3)^3/2^3 - 2^6/2^3" (right side simplifies to" 2^3# )

=# (2^3 xx 3^3)/2^3 - 2^3#

=# (cancel2^3 xx 3^3)/cancel2^3 - 2^3#

=#3^3 - 2^3#

=#27-8 = 19#