What is #(6a^2-5a-3)+(a^2+a)#?

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Answer 1 · 2017-02-09T13:40:07

#7a^2 - 4a - 3# or #(7a + 3)(a - 1)#

First, remove all the terms from their parenthesis. Be careful to manage the signs of each individual term correctly.

#6a^2 - 5a - 3 + a^2 + a#

Next, group like terms together:

#6a^2 + a^2 - 5a + a - 3#

#6a^2 + 1a^2 - 5a + 1a - 3#

Now, combine like terms together:

#(6 + 1)a^2 + (-5 + 1)a - 3#

#7a^2 + (-4)a - 3#

#7a^2 - 4a - 3#

This can also be factored to:

#(7a + 3)(a - 1)#