# What is 7\cdot 4^ { 2} \div 8- 12?

Oct 19, 2016

#### Explanation:

To solve this use the order of operation. PEMDAS
( if you get hurt in PE class call an MD ASap)

The first step is to do ${4}^{2}$ exponents. This is the same as four times four (The E = exponents

# 4 xx 4 = 16

Next divide by 8 because $\frac{16}{8}$ the __ acts as a parenthesis
(The P equals parenthesis )

$\frac{16}{8}$ = 2

Next multiply by 7 (MD means multiply and divide working from left to right. MD a doctor is one person so do multiplication and division at the same time)

$7 \times 2 = 14$

Last subtract positive 12 (AS addition and subtraction. ASAP or as soon as possible is one time so do addition and subtraction working from left to right, do addition and subtraction at the same time.

14 - 12 = 2

Oct 19, 2016

$2$

#### Explanation:

There are 2 terms. Keep them separate till the last step.

Within each term do powers first, then the multiplication and division.

$\textcolor{b l u e}{7 \times {4}^{2} \div 8} \textcolor{red}{- 12}$

Rewrite in a different form:

$= \frac{7 \times 16}{8} - 12$

$= \frac{7 \times {\cancel{16}}^{2}}{\cancel{8}} - 12$

$= 14 - 12$

$= 2$