Question

What is `(9+7i)-(6-2i)`?

Answer 1

`(9+7i)−(6−2i)` is complex number `(6−2i)` subtracted from another complex number `(9+7i)`. Its value is `3+9i`

Explanation:

A complex number is described as `a+ib`, where `a` and `b` are real numbers and `i^2=-1` i.e. `i=sqrt-1`.

Hence `(9+7i)−(6−2i)` is complex number `(6−2i)` subtracted from another complex number `(9+7i)`.

To find `(9+7i))−(6−2i)` solve just like any expression remembering `i=sqrt-1`. Hence

`(9+7i))−(6−2i)`

= `9+7i-6+2i`

= `3+9i`.