What is an ordered pair of the function d(t)=35t?

$\left(0 , 0\right) , \left(1 , 35\right) , \left(- 1 , - 35\right)$

Explanation:

An ordered pair is a set of numbers - one of which is the independent variable and the other is the result. And since that just sounds like a bunch of words, let's just do it this way:

$\left(t , d \left(t\right)\right)$ - this is our format.

Ok, let's do a few of these to get the hang of it. One of my favourite numbers to drop into anything like this is the number $0$. Ok, so we have:

$t = 0$

And what is $d \left(t\right)$ when $t = 0$?

$d \left(t\right) = 35 t = 35 \left(0\right) = 0$

So we have an ordered pair:

$\left(0 , 0\right)$

Let's do it again with $t = 1$:

$d \left(t\right) = 35 \left(1\right) = 35 \left(1\right) = 35$

And so we have

$\left(1 , 35\right)$

Let's do it again with $t = - 1$:

$d \left(t\right) = 35 \left(1\right) = 35 \left(- 1\right) = - 35$

And that give us $\left(- 1 , - 35\right)$