Question

What is `d/dx(ln((x+1)/(x-1)))`?

Answer 1

`(-2)/(x^2-1)`

Explanation:

`d/dx(ln((x+1)/(x-1)) = d/dx(ln(x+1)-ln(x-1))`

`= 1/(x+1)-1/(x-1)`

`= ((x-1)-(x+1))/((x+1)(x-1))`

`= (-2)/(x^2-1)`