What is #f(x) = int e^x dx# if #f(0)=-2 #?

1 Answer
Shreya
Mar 28, 2018

#e^x -3#

Explanation:

We have, #f(x)=inte^xdx# which comes out to be #e^x +C# where #C# is the constant of integration.
We also have #f(0)=-2#.Plugging in this value in the expression we derived earlier, we get #e^0 +C#=-2 or #C#=-2-1 which is -3. Thus,the expression comes out to be #e^x -3#

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