What is #i^4#? Precalculus Complex Numbers in Trigonometric Form Powers of Complex Numbers 1 Answer Harish Chandra Rajpoot Jul 2, 2018 #i^4=1# Explanation: We know that #i=\sqrt{-1}\ or \ i^2=-1# #\therefore i^4=(i^2)^2=(-1)^2=1# Answer link Related questions How do I use DeMoivre's theorem to find #(1+i)^5#? How do I use DeMoivre's theorem to find #(1-i)^10#? How do I use DeMoivre's theorem to find #(2+2i)^6#? What is #i^2#? What is #i^3#? How do I find the value of a given power of #i#? How do I find the #n#th power of a complex number? How do I find the negative power of a complex number? Write the complex number #i^17# in standard form? How do you simplify #i^-33#? See all questions in Powers of Complex Numbers Impact of this question 14638 views around the world You can reuse this answer Creative Commons License