Question

What is `int sinx cosx`?

Answer 1

`\intcos(x)sin(x)dx=\frac{-1}{4}cos(2x)+c`

Explanation:

Given equation is `\intcos(x)sin(x)dx`

I believe you're familiar with the trigonometric identity `sin(2\theta)=2sin(\theta)cos(\theta)`
So, the equation becomes `\frac{1}{2}\intsin(2x)dx`

I'm sure you know what to do from here to get the equation I got there above.

Answer 2

There are 3 equivalent results:
`(sin^2x)/2+C`
`-(cos^2x)/2+C`
`-(cos(2x))/4+C`

Explanation:

I found an awesome video about this:
link