# What is inverse cot^-1(-sqrt(3))?

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Mar 6, 2015

${\cot}^{-} 1 \left(- \sqrt{3}\right) = \frac{5 \pi}{6}$

When you are solving inverse trigonometry functions, you have to ask yourself the following question: Where does the cotangent function equal $- \sqrt{3}$?

Because cotangent is equal to $\frac{\cos}{\sin}$, you can see that the inverse cotangent of $- \sqrt{3}$ is $\frac{5 \pi}{6}$.

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