What is #K_(eq)# for the reaction #2SO_3(g) #⇌ #2SO_2(g)# + # O_2 (g)#?

1 Answer
Jul 10, 2016

Answer:

Unknown at this stage. But we can certainly write the equilibrium expression.

Explanation:

#2SO_3(g)rightleftharpoons2SO_2(g) + O_2(g)#

#K_c# #=# #([SO_2(g)]^2[O_2(g)])/([SO_3(g)]^2)#

This can be turned into an expression relating the partial pressures of each component at equilibrium.