What is #ln(e^x)#?

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Gió Share
Nov 11, 2015

Answer:

It is exactly #x#.

Explanation:

You are looking for a number that is the exponent of the base of #ln# which gives us the integrand, #e^x#;
so:
the base of #ln# is #e#;
the number you need to be the exponent of this base to get #e^x# is.....exactly #x#!!!
so:
#ln(e^x)=log_e(e^x)=x#

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