Question

What is `P(x)` for `n=3. x = 0, p = 0.8`?

Answer 1

`P(0)=0.008`.

Explanation:

For the Binomial Distribution,

`P(x)=""_nC_xp^xq^(n-x), x=0,1,2,...,n; q=(1-p).`

In our Example, `n=3, x=0, &, p=0.8 rArr q=1-p=0.2`

`:. P(0)=""_3C_0(0.8)^0(0.2)^(3-0)=(1)(1)(0.008)=0.008`.

Enjoy Maths.!