# What is pressure of a gas that expands to a volume of 20.0 liters, if the gas's initial pressure is 2.50 atm and initial volume is 5.00 L?

At constant temperature, ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$, which is Boyle's law.
At constant temperature, ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$, which is Boyle's law.
${P}_{2}$ $=$ $\frac{2.50 \cdot a t m \times 5.00 \cdot L}{20 \cdot L}$ $=$ ??atm