What is #sin^-1(sqrt3/2)#?

1 Answer
Nghi N
Apr 8, 2018

#x = pi/3 + 2kpi#
#x = (2pi)/3 + 2kpi#

Explanation:

#sin x = sqrt3/2# --> find arcsin x
Trig table gives: #x = pi/3#
Unit circle gives another arc x that has the same sin value #(sqrt3/3)#:
#x = pi - pi/3 = (2pi)/3#
General answers
#x = pi/3 + 2kpi#
#x = (2pi)/3 + 2kpi#

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