What is #sqrt15/sqrt48#?

1 Answer
George C.
Jan 1, 2016

#sqrt(15)/sqrt(48) = sqrt(5)/4 ~~ 0.559017#

Explanation:

If #a, b >= 0# then #sqrt(ab) = sqrt(a)sqrt(b)#

So:

#sqrt(15)/sqrt(48)=(color(red)(cancel(color(black)(sqrt(3))))sqrt(5))/(color(red)(cancel(color(black)(sqrt(3))))sqrt(16))=sqrt(5)/4#

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