What is the acceleration experienced by a car that takes 10 s to reach 27 m/s from rest?

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Answer 1 · 2018-05-21T00:45:04

#2.7 m/s^2#

Given: a car takes #10# s to reach #27 m/s# from rest.

acceleration #= a = (v_f - v_i)/t#,

where #v_f = #velocity final and #v_i = #velocity initial

#a = (27 - 0)/10 = 2.7 m/s^2#

Answer 2 · 2018-05-21T12:51:55

#2.7 \ "m/s"^2#

Acceleration is given through the equation,

#a=(v-u)/t#

where:

#v# is the final velocity of the object

#u# is the initial velocity of the object

#t# is the time taken

Here, since the car was at rest, it was stationary, and so #u=0#.

#:.a=v/t#

#=(27 \ "m/s")/(10 \ "s")#

#=2.7 \ "m/s"^2#