What is the acceleration experienced by a car that takes 10 s to reach 27 m/s from rest?

2 Answers
May 21, 2018

Answer:

#2.7 m/s^2#

Explanation:

Given: a car takes #10# s to reach #27 m/s# from rest.

acceleration #= a = (v_f - v_i)/t#,

where #v_f = #velocity final and #v_i = #velocity initial

#a = (27 - 0)/10 = 2.7 m/s^2#

May 21, 2018

Answer:

#2.7 \ "m/s"^2#

Explanation:

Acceleration is given through the equation,

#a=(v-u)/t#

where:

  • #v# is the final velocity of the object

  • #u# is the initial velocity of the object

  • #t# is the time taken

Here, since the car was at rest, it was stationary, and so #u=0#.

#:.a=v/t#

#=(27 \ "m/s")/(10 \ "s")#

#=2.7 \ "m/s"^2#