# What is the acceleration experienced by a car that takes 10 s to reach 27 m/s from rest?

May 21, 2018

$2.7 \frac{m}{s} ^ 2$

#### Explanation:

Given: a car takes $10$ s to reach $27 \frac{m}{s}$ from rest.

acceleration $= a = \frac{{v}_{f} - {v}_{i}}{t}$,

where ${v}_{f} =$velocity final and ${v}_{i} =$velocity initial

$a = \frac{27 - 0}{10} = 2.7 \frac{m}{s} ^ 2$

May 21, 2018

$2.7 \setminus {\text{m/s}}^{2}$

#### Explanation:

Acceleration is given through the equation,

$a = \frac{v - u}{t}$

where:

• $v$ is the final velocity of the object

• $u$ is the initial velocity of the object

• $t$ is the time taken

Here, since the car was at rest, it was stationary, and so $u = 0$.

$\therefore a = \frac{v}{t}$

$= \left(27 \setminus \text{m/s")/(10 \ "s}\right)$

$= 2.7 \setminus {\text{m/s}}^{2}$