# What is the acceleration of a car stopping with 254 N of force if it has a mass of 2500 kg?

Mar 10, 2017

$- 0.1016 m {s}^{- 2}$

#### Explanation:

using N2L

F=ma~

$254 = 2500 a$

$a = \frac{254}{2500} = 0.1016 m {s}^{- 2}$

since this is STOPPING the car it is a negative acceleration

so $a = - 0.1016 m {s}^{- 2}$

Mar 11, 2017

$F = m a$
$254 = \left(2500\right) a$
$\frac{254}{2500} = a$
0.1016m/s²=a
when the car is stopping, negative acceleration(deceleration) has been produced
a=-0.1016 m/s²#