# What is the angular momentum of a rod with a mass of 15 kg and length of 7 m that is spinning around its center at 5 Hz?

Jan 5, 2017

The angular momentum is $= 1924.2 k g m {s}^{- 1}$

#### Explanation:

The angular momentum is $L = I \omega$

where $I$ is the moment of inertia

and $\omega$ is the angular velocity

For a rod, the moment of inertia is $I = \frac{m {L}^{2}}{12}$

$m =$mass of the rod

$L =$ length of the rod

So, $I = 15 \cdot {\left(7\right)}^{2} / 12 = \frac{245}{4} k g {m}^{2}$

$\omega = 5 \cdot 2 \pi = 10 \pi r a {\mathrm{ds}}^{-} 1$

$L = \frac{245}{4} \cdot 10 \pi = 1924.2 k g m {s}^{- 1}$