# What is the angular momentum of a rod with a mass of 5 kg and length of 4 m that is spinning around its center at  1 7 Hz?

Nov 16, 2016

The angular momentum is $= \frac{340}{3} k g {m}^{2} {s}^{- 1}$

#### Explanation:

The angular momentum is $L = I \omega$

Where, $I =$moment of inertia

and $\omega =$ angular velocity

The moment of inertia of the rod is $= \frac{m {l}^{2}}{12}$

$m = 5 k g$

$l = 4 m$

Therefore, $I = \frac{5 \cdot {4}^{2}}{12} = \frac{20}{3} k g {m}^{2}$

$\omega = 17 H z$

So, $L = 17 \cdot \frac{20}{3} = \frac{340}{3} k g {m}^{2} {s}^{- 1}$