What is the angular momentum of a rod with a mass of #5 kg# and length of #4 m# that is spinning around its center at # 1 1 Hz#?

1 Answer

Answer:

The angular momentum(L)=5526.4J-s.

Explanation:

Angular momentum #L=mr^2(omega)#
Here the object is rotated on its own centre, so we will be considering its length as radius.
As we know #omega=2xxpixxnu#
Substitute frequency value in above equation, we get #omega=69.08rad /sec#
Now substitute the angular velocity(#omega#) value in initial equation, we get #L= 5kg×16m^2×69.08rad /s#
#:. L=5526.4# Joules-sec