# What is the angular momentum of a rod with a mass of 5 kg and length of 4 m that is spinning around its center at  1 1 Hz?

Angular momentum $L = m {r}^{2} \left(\omega\right)$
As we know $\omega = 2 \times \pi \times \nu$
Substitute frequency value in above equation, we get $\omega = 69.08 r a \frac{d}{\sec}$
Now substitute the angular velocity($\omega$) value in initial equation, we get L= 5kg×16m^2×69.08rad /s
$\therefore L = 5526.4$ Joules-sec