What is the angular momentum of a rod with a mass of #8 kg# and length of #6 m# that is spinning around its center at #3 Hz#?

1 Answer
Jan 25, 2018

Answer:

The angular momentum is #=452.4kgm^2s^-1#

Explanation:

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

The mass of the rod is #m=8kg#

The length of the rod is #L=6m#

The moment of inertia of a rod, rotating about the center is

#I=1/12*mL^2#

#=1/12*8*6^2= 24 kgm^2#

The frequency is #f=3Hz#

The angular velocity is #omega=2pif=2*3*pi=6pirads^-1#

The angular momentum is

#L=Iomega=24*6pi=452.4kgm^2s^-1#