Question

What is the angular momentum of a rod with a mass of `8 kg` and length of `6 m` that is spinning around its center at `5 Hz`?

Answer 1

The angular momentum is `=754kgm^2s^-1`

Explanation:

The angular momentum is `L=Iomega`

where `I` is the moment of inertia

For a rod (rotating about the center), `I=(mL^2)/12`

So, `I=8*(6)^2/12=24kgm^2`

The angular velocity is

`omega=5*2pi=10pirads^-1`

So,

The angular momentum is

`L=24*10pi=754kgm^2s^-1`